Three-phase line and phase quantities
Distinguish line-to-line voltage, winding voltage and line current in balanced wye and delta connections.
Learning goal: Use √3 in the correct place and calculate line current from total three-phase kVA.
Prepared by Power Stations Worldwide. Sources checked on 30 September 2026; not independently engineering peer reviewed.
The essentials
Wye (star): voltage changes
In a balanced wye connection, each winding is connected between a line and the star point. Line-to-line voltage magnitude is √3 times winding voltage; line current equals winding current. Line-to-neutral equals winding voltage when the neutral references that star point.
Delta: current changes
In a balanced delta connection, each winding is across two lines, so winding voltage equals line-to-line voltage. Line-current magnitude is √3 times winding current. These are magnitude relationships; phasor angle relationships also matter.
Do not multiply by three twice
S = √3 VLL IL gives total three-phase apparent power. Equivalently, S = 3 Vphase Iphase using corresponding winding values for a balanced load. Do not insert a line-to-neutral voltage into the line-to-line formula.
Wye and delta quantities
Worked example
A balanced 25 kVA wye load at 400 V line-to-line
Given
- Total apparent power S = 25 kVA = 25,000 VA
- VLL = 400 V RMS
- Balanced wye-connected load
Formula toolbox
- Balanced wye: VLL = √3 Vphase; IL = Iphase
- Balanced delta: VLL = Vphase; IL = √3 Iphase
- Total S = √3 VLL IL = 3 Vphase Iphase
Calculate step by step
- Winding voltage: Vphase = 400 / √3 ≈ 230.94 V.
- Line current: IL = 25,000 / (√3 × 400) ≈ 36.08 A.
- Wye winding current equals line current: Iphase ≈ 36.08 A.
- Cross-check with unrounded values: 3 × Vphase × Iphase = 25,000 VA.
230.94 V per winding · 36.08 A per line
400 V and 230 V are often nominal rounded labels; 400/√3 is about 230.94 V. Neutral current is zero only for the ideal balanced sinusoidal set—not for every real installation.
Results are rounded only for display. Reproduce the calculations using unrounded intermediate values.
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- VLL = √3 Vphase. Wye: VLL = √3 Vphase and IL = Iphase. Delta uses a different current relationship.
- About 14.43 A. IL = 10,000 / (√3 × 400) ≈ 14.43 A. Use VA, not kVA, with volts.
Curriculum connection: MIT 6.061 (Spring 2011). Its readings include 2007 notes; some equations use peak rather than RMS amplitudes. This lesson states its own value conventions and uses original diagrams, numbers and quiz questions. No MIT affiliation or endorsement is claimed.
Textbook references
Suggested technical background for this topic. These books are further reading, not proof that every explanation was checked against every edition. See the full bibliography and review scope.
- Electric CircuitsBalanced three-phase circuits and phase/line relationships.
- Electrical Machines, Drives and Power SystemsThree-phase circuits and transformer connections.